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Angles of a Triangle Test-2
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Angles of a Triangle Test-2 …
Angles of a Triangle Test-2 Problems
Problem 1 :
ABC is a triangle, [BD] and [CD] bisector, if m (BDC) = 52 °; How many degrees is m (BAC) = x?
![iç açıortay dış açıortay soruları](https://www.dersgeometri.com/wp-content/uploads/2019/07/ic-aciortay-dis-aciortay-sorulari.jpg)
Problem 2 :
ABC is a triangle, [BD] and [CD] bisector, if m (BDC) = 50 °; How many degrees is m (CAD) = x?
![dış teğet çember soruları](https://www.dersgeometri.com/wp-content/uploads/2019/07/dis-teget-cember-sorulari.jpg)
Problem 3 :
In ABC triangle; D is the center of the outer tangent circle, if m (ADB) = x, m (BDC) = y, m (BAC) = 7x-5 °, m (ACB) = y-20 °; How many degrees is x?
![dış teğet çemberin merkezi soruları](https://www.dersgeometri.com/wp-content/uploads/2019/07/dis-teget-cemberin-merkezi-sorulari.jpg)
Problem 4 :
If KN parallel [CP, m (ACB) = m (BCP), | AC | = | BC |, m (CAK) = 60 °; How many degrees is m (NAB) = x?
![üçgende açılar çözümlü sorular 9. sınıf](https://www.dersgeometri.com/wp-content/uploads/2019/07/ucgende-acilar-cozumlu-sorular-9.-sinif.jpg)
Problem 5 :
If [AD parallel NP, [AC] bisector, | AB | = | CD |, m (ABN) = 2m (PBD); How many degrees is m (DCA) = x?
![üçgende açılar soru](https://www.dersgeometri.com/wp-content/uploads/2019/07/ucgende-acilar-soru.jpg)
Problem 6 :
ABC is a triangle, | AB | = | AE | = | BD |, if m (EAC) = 24 °, m (CBD) = 30 °; How many degrees is m (ACB) = x?
![üçgenler çözümlü sorular](https://www.dersgeometri.com/wp-content/uploads/2019/07/ucgenler-cozumlu-sorular.jpg)
Problem 7 :
ABC triangle, if | AP | = | PC |, | FA | = | FB | = | FP |, if m (ACB) = 33 °; How many degrees is m (BAF) = x?
![açılar çözümlü sorular](https://www.dersgeometri.com/wp-content/uploads/2019/07/acilar-cozumlu-sorular.jpg)
Problem 8 :
If | AB | = | BC | = | CD | = | DE |, if m (EDC) = m (CDB); How many degrees is m (DAE) = x?
![açılar soruları](https://www.dersgeometri.com/wp-content/uploads/2019/07/acilar-sorulari.jpg)
Angles of a Triangle Test-2 Solutions
Solution of Problem 1 :
m (BDC) = 52 °, formed by the intersection of triangle ABC with an inner bisector and an outer bisector, will be half the angle m (BAC), so m (BAC) = 2.52 ° = 104 °.
![bir dış açıortay bir iç açıortay](https://www.dersgeometri.com/wp-content/uploads/2019/07/bir-dis-aciortay-bir-ic-aciortay.jpg)
Solution of Problem 2 :
Since the triangle ABC intersects an inner bisector and an outer bisector, m (BAC) = 100 °. If there is any two of the two outer bisectors in the triangle, the third is the bisector. (Point D is the center of the outer tangent circle of triangle ABC.) In this case, m (CAD is CAD. ) = x = 40 °.
![dış teğet çember ile ilgili çözümlü sorular](https://www.dersgeometri.com/wp-content/uploads/2019/07/dis-teget-cember-ile-ilgili-cozumlu-sorular.jpg)
Solution of Problem 3 :
[AD], [BD], [CD] is bisector. ABC triangle; With the inner bisector of [BD], 2y = 7x-5 ° from the outer bisector of [CD], and 2x = y-20 ° from the outer bisector [AD] with the inner bisector of [BD].
![iki dış açıortay ile bir iç açıortay](https://www.dersgeometri.com/wp-content/uploads/2019/07/iki-dis-aciortay-ile-bir-ic-aciortay.jpg)
Solution of Problem 4 :
Equilateral angles from inside angles are 30 degrees. In an isosceles triangle, m (BAC) = 75 °. From the right angle x = 45 °.
![üçgende açılar soru çözümü](https://www.dersgeometri.com/wp-content/uploads/2019/07/ucgende-acilar-soru-cozumu.jpg)
Solution of Problem 5 :
If we say m (BAC) = m (CAD) = a, then m (ABN) = 2a from inside angles. If m (ABN) = 2a then m (PBD) = a. M (ADB) = a (internal inverse angle). | AC | = | CD | Since | AB | = | AC | m (ACB) = 2a (outer angle). In the triangle ABC, m (ACB) = m (CBA) = 2a. Then 5a = 180 °, a = 36 °. x = 108 °.
![üçgende açılar soruları ve çözümleri](https://www.dersgeometri.com/wp-content/uploads/2019/07/ucgende-acilar-sorulari-ve-cozumleri.jpg)
Solution of Problem 6 :
| AB | = | AE |; m (AEB) = m (EBA) = b + 30 °, | AB | = | BD |; m (ADB) = m (BAD) = a + 24 ° A + 2b = 120 ° in triangle ABE, 2a + b = 132 ° in triangle USA. From the solution of a system of equations with two unknowns, b = 36 °. x = 42 ° is calculated.
![üçgende açılar soruları ve cevapları](https://www.dersgeometri.com/wp-content/uploads/2019/07/ucgende-acilar-sorulari-ve-cevaplari.jpg)
Solution of Problem 7 :
Since a + b = 66 ° (outer angle), 2x + 2 (a + b) = 180 ° in triangle ABP; 2x = 180 ° -132 °, x = 24 °.
![üçgende açılar çözümlü sorular](https://www.dersgeometri.com/wp-content/uploads/2019/07/ucgende-acilar-cozumlu-sorular.jpg)
Solution of Problem 8 :
From top to bottom, in the triangle, equilateral angle, outer angle, equilateral angle in triangle, equilateral angle in triangle, outer angle in triangle, equilateral angle are written. The interior angles of the triangle are added together and the angle x is calculated.
![matematik üçgenler test](https://www.dersgeometri.com/wp-content/uploads/2019/07/matematik-ucgenler-test.jpg)
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Angles of a Triangle test-2 PDF
Course Geometry offers Geometry textbook in pdf format that can be downloaded free of charge. Students can view the angles of a triangle test-2 pdf, which is important for university entrance exam, which aims to improve students’ problem solving skills.